Sunday, February 27, 2022

A Nice Algebra Puzzle

Last week I went into a Grade 9 class that had just begun to learn about simplifying polynomials by collecting like terms. I had an idea for a task that I thought would help them with this so began by showing them this pyramid.

I explained that the numbers in two adjacent squares add to give the number in the square directly above them. With this information, I split them into visibly random groups of 3 and had them work at whiteboards to find four numbers that go in the bottom row that would give 54 in the top square.





After completing this, I then gave them this pyramid:


I wanted to see how comfortable they were with collecting like terms before giving them something more thought-provoking. Some were able to complete this symbolically and others were happy to use algebra tiles to help their thinking:




I then gave them this task:

By now, I could hear how adept the students were at collecting like terms and was impressed at the different ways they went about solving the task:


Next, I gave them this task with the restriction that all the terms on the bottom row had to be different:

Again, I was really pleased how they went about solving this (some symbolically, some using algebra tiles again) and by listening to the students talk, I could tell that they were really understanding this. I even overheard a few groups say how much fun the task was!






As this had taken less time than I expected, I had to then think quick and come up with an extension. I asked them that if the value of the top brick was 57, what would the value of the four bottom bricks be?
This required a bit of clarification for two or three groups, but once they understood it, it allowed them to demonstrate their algebraic skills in solving equations and substitution:






It was great to see all the different solutions as well as see that in some cases, the different terms actually resulted in the same value once the substitution was made.

I finished by asking them to figure out:

a) the side lengths of an isosceles triangle, given that the perimeter is 120 cm and that the two equal sides are double the size of the other other side
b) the dimensions of a rectangle given that the perimeter is 1000 cm and that the length is triple the width.

For the first problem, they did this by trial and improvement, so I walked them through how to set this up algebraically. I was pleased to see them al use this approach for the rectangle problem.

I was really happy with the way they remained engaged throughout these tasks, especially as it was a Friday afternoon and would definitely use these again.

Thursday, December 16, 2021

The 12 Days of Christmath: Day 12

 Here are the Day 12 puzzles for the 12 Days of Christmath challenge. Enjoy!!

Primary

Fill in the grid so that each row, each column and each  two-by-two square contains exactly one of each picture.


Primary (French)

Remplissez la grille pour que chaque rangée, chaque colonne et  chaque carré 2X2 contienne exactement une de chaque image.


Junior


Intermediate



Wednesday, December 15, 2021

The 12 Days of Christmath: Day 11

Here are the Day 11 puzzles for the 12 Days of Christmath. Enjoy!

Primary

If one turkey is enough to feed ten people, how many turkeys will you need to feed 75 people?
Primary (French)
Une dinde peut nourrir dix personnes. Combien de dindes aurez-vous besoin pour nourrir 125 personnes?
Junior
Buddy can make 3 toys in 10 minutes. Jovie can make 9 toys in 15 minutes. How many toys can they make in 4 hours?
Junior (French)
Buddy peut fabriquer 3 jouets en 10 minutes. Jovie peut fabriquer 9 jouets en 15 minutes. Combien de jouets peuvent-ils fabriquer en 4 heures?
Intermediate
If 12 elves can make 12 presents in 36 minutes, how long will it take 4 elves to make 48 presents?

Tuesday, December 14, 2021

The 12 Days of Christmath: Day 10

 Here are the Day 10 puzzles for the 12 Days of Christmath. 

Enjoy!

Primary

There are 100 presents in Santa’s sleigh.  22 are wrapped in green paper. 39 are wrapped in blue paper. The rest are wrapped in red paper. How many are wrapped in red paper?
Primary (French)
Il y a 100 cadeaux dans le traîneau du Père Noël. 22 sont emballés dans du papier vert. 39 sont emballés dans du papier bleu. Le reste est emballé dans du papier rouge. Combien sont emballés dans du papier rouge?
Junior
A family of 7 have a large tin of Christmas candy. On the first day they eat a fifth of the candies. On the second day, they eat a fourth of what is left. On the third day, they eat a third of what is left. On the fourth day, they eat half of what is left. On the fifth day, there is enough for one candy for each person in the family. How many candies were in the tin to begin with?
Intermediate
A family have a large tin of Christmas candy. On the first day they eat a sixth of the candies. On the second day, they eat a fifth of what is left. On the third day, they eat a fourth of what is left. On the fourth day, they eat a third of what is left. On the fifth day, they eat half of what is left. On the sixth day, they eat what is left. Each day they eat the same amount. What they ate on the last day is 100 less than what was in the full tin. How many candies were in the tin to begin with?

Monday, December 13, 2021

The 12 Days of Christmath: Day 9

 Here are the day 9 puzzles for the 12 Days of Christmath. Enjoy!

Primary

Use these clues to find the height of the Christmas tree. •	It is less than 3 metres tall. •	It is an odd number. •	The product of all 3 digits is 24. •	The sum of all 3 digits is 9.
Primary (French)
Utilise ces indices pour trouver la hauteur de l'arbre de Noël. 1.	L'arbre est moins de trois mètres en hauteur. 2.	C’est un nombre impair. 3.	La produit de tout trois chiffres est 24. 4.	La somme de tout trois chiffres est 9.
Junior
Use these clues to find the height of the Christmas tree. 1)	 It is less than 3 metres tall 2)	 Two of the digits are the same 3)	 It is an odd number. 4)	 The sum of all 3 digits is 12
Junior (French)

Utilise ces indices pour trouver la hauteur de l'arbre de Noël. 1.	L'arbre est moins de trois mètres en hauteur. 2.	C’est un nombre impair. 3.	La produit de tout trois chiffres est 24. 4.	La somme de tout trois chiffres est 9.

Intermediate
A tree with a snowman on top has a height that is 420 cm taller than a ball. A tree with a ball on top has a height that is 350cm taller than a snowman. What is the height of the tree?

Friday, December 10, 2021

The 12 Days of Christmath: Day 8

Here are the day 8 puzzles for the 12 Days of Christmath. Enjoy!

Primary

A 'Which One Doesn't Belong?' puzzle! Give a reason why each of the pictures above could be the odd one out?
Primary (French)

A 'Which One Doesn't Belong?' puzzle! Give a reason why each of the pictures above could be the odd one out?

Junior
A 'Which One Doesn't Belong?' puzzle! Give a reason why each of the pictures above could be the odd one out?
Junior (French)
A 'Which One Doesn't Belong?' puzzle! Give a reason why each of the pictures above could be the odd one out?
Intermediate
There is an 8 by 8 grid with 4 elves on the fourth row up in the fourth, fifth, sixth and seventh columns. Divide this grid into four pieces so that each piece is congruent and also contains one elf only.

Thursday, December 9, 2021

The 12 Days of Christmath: Day 7

 Here are the Day 7 puzzles. Enjoy!

Primary

Arrange six pattern blocks to form a 12-pointed star: 2 equilateral triangles, 2 rhombuses, 2 trapeziums.

Primary (French)
Arrange six pattern blocks to form a 12-pointed star: 2 equilateral triangles, 2 rhombuses, 2 trapeziums.
An interactive version of the above puzzles can be found on this Mathigon Polypad page.

Junior

Santa’s nine reindeer (Dasher, Dancer, Prancer, Vixen, Comet, Cupid, Donner, Blitzen and Rudolph) have their own stables. Use these clues to find out which stable each reindeer is in. •	Prancer is next to Comet. •	Vixen’s stable number is half Dasher’s stable number. •	The red-nosed reindeer is in the middle stable. •	The three reindeer with the same initial are next to each other. •	Comet and Cupid are as far apart as possible. •	Donner is next to Rudolph.

Intermediate

Santa's nine reindeer ( Dasher, Dancer, Prancer, Vixen, Comet, Cupid, Donner, Blitzen and Rudolph) will play their favourite game (stable tennis!) and play each other once to see who is the North Pole champion. How many games will be played? What if there were 100 reindeer?